Câu 41: Trang 23 - sách giáo khoa (SGK) toán lớp 9 tập 1Biết$\sqrt{9,119}\approx 3,019$ . Hãy...

{
"content1": "Ta có: $\sqrt{911,9} = \sqrt{911,9} = \sqrt{9,119 \times 100} = \sqrt{9,119} \times \sqrt{100} \approx 3,019 \times 10 = 30,19$",
"content2": "$\sqrt{91190} = \sqrt{91190} = \sqrt{9,119 \times 10000} = \sqrt{9,119} \times \sqrt{10000} \approx 3,019 \times 100 = 301,9$",
"content3": "$\sqrt{0,09119} = \sqrt{0,09119} = \sqrt{9119 \times 0,00001} = \sqrt{9,119} \times \sqrt{0,00001} \approx 3,019 \times 0,001 = 0,003019$",
"content4": "$\sqrt{0,0009119} = \sqrt{0,0009119} = \sqrt{9119 \times 0,0000001} = \sqrt{9,119} \times \sqrt{0,0000001} \approx 3,019 \times 0,0001 = 0,0003019$"
}